Saved Bookmarks
| 1. |
Directions: In the following question, two statements are numbered as Quantity I and Quantity II. On solving these statements, we get quantities I and II respectively. Solve both quantities and choose the correct option.Quantity I: Three years ago, the ratio of age of son and father was 1 : 8. After three years the ratio of their age will become 5 : 19. What is the present age of son?Quantity II: Three years ago, the ratio of age of son and mother was 1 : 9. After two years the ratio of their age will become 1 : 4. What is the present age of son?1. Quantity I > Quantity II2. Quantity I < Quantity II3. Quantity I = Quantity II4. Quantity I ≥ Quantity II5. Quantity I ≤ Quantity II |
|
Answer» Correct Answer - Option 1 : Quantity I > Quantity II Solving for Quantity I: Given: Three years ago, the ratio of age of son and father = 1 : 8 After three years, the ratio of age of son and father = 5 : 19 Calculations: Let three years ago from present, the age of son and father be x and 8x years respectively. So, After 6 years ratio of their age will be 5 : 19 ⇒ (x + 6)/(8x + 6) = 5 : 19 ⇒ 19x + 114 = 40x + 30 ⇒ 21x = 84 ⇒ x = 4 Present age of son = x + 3 ⇒ 4 + 3 ⇒ 7 ∴ Present age of son is 7 years. Solving for Quantity II: Given: Three years ago, the ratio of age of son and mother = 1 : 9 After three years the ratio of age of son and mother = 1 : 4 Calculations: Let three years ago from present, the age of son and mother be x and 9x years respectively. So, After 5 years ratio of their age will be 1 : 4 ⇒ (x + 5)/(9x + 5) = 1 : 4 ⇒ 4x + 20 = 9x + 5 ⇒ 5x = 15 ⇒ x = 3 Present age of son = x + 3 ⇒ 3 + 3 ⇒ 6 ∴ Present age of son is 6 years. ∴ Quantity I > Quantity II |
|