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Discuss in detail about the variation of internal energy with respect to variation thermodynamic processes. |
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Answer» Solution :Mathematics statement of the FIRST law of thermodynamics is `DeltaU=q+w` Case 1 : For a cyclic process involving isothermal expansion of an ideal gas `DeltaU=0 , :. Q=-w` In other words,during a cyclic process , the amount of heat absorbed by the system in EQUAL to work done by the system. Case 2 : For an isolated process ( no change in volume ) there is no work of expansion. `DeltaV=0, w=0 ,DeltaU=q_(v)` In other words , during isochoric process , the amount of heat supplied to the system is CONVERTED fl to its internal energy . Case 3 : For an adiabatic process there is no change in heat i.e. q = 0 . Hence `q=0,DeltaU=w` In other words, in a adiabatic process , the decrease in internet energy is exactly equal to the work done by the system on its surroundings. in the pressure . P remains constant . Hence `DeltaU=q+w` `DeltaU=q-PDeltaV` n other words , inan isolated process a part of heat absorbed by the system is used for PV expansion work and the remaining is added to the internal energy of the system. |
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