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Discuss the continuity of the function f defined byf(x) = 1/(x-1) , x ne 1 |
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Answer» Solution :For any real number c, for `c ne 1` we have ` underset(X to c)LIM f(x) = underset(x to c) lim 1/(x -1) = 1/(c-1) ` ALSO, since for ` c ne 1 f(c)= 1/ (c-1)` we have ` underset(x to c) f(x) = f(c)` and hence f is CONTINUOUS at every point in the domain of f is a continuous function. |
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