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Discuss the diagonal relationship of Be and AI with regard to (i) action of alkali and (ii) the strucutre of their chloride. |
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Answer» Solution :(i) Be and AI both react with NaOH to form sodium beryllate and sodium me ALUMINATE respetively. Be dissolves in excess of NaOH to form `[Be(OH)_(4)]^(2)` where as forms `[AI(OH)_(6)]^(3-)` in exces of NaOH `2H_(2) O + BE + 2NaOH to Na_(2) [Be (OH)_(4)]` (Salium beryllali) + `H_(2)` `2AI + 6NaOH + 6H_(2) O to 2Na_(3) [AI (OH)_(6)]` (Sodium meta ilunivali + `3H_(2)` (ii) Be `CI_(2)` is electron deficient, THEREFORE, has POLYMERIC chain structure In solid state. ` AICI_(3)` is also electron deficient. It exists as dimmer, i.e., `AI_(2) CI_(6)`
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