Saved Bookmarks
| 1. |
Discuss the formation of N2, molecule using MO Theory. |
|
Answer» Solution :(i) ELECTRONIC CONFIGURATION of N atom `1s^(2)2s^(2)2p^(3).` (II) Electronic configuration of `N_(2)` molecule is: `sigma1s^(2)" "sigma**1s^(2)" "sigma2s^(2)" "sigma**2s^(2)" "pi2p_(y)^(2)" "pi2p_(z)^(2)" "sigma2p_(x)^(2)` (iii) Bond order `= (N_(b)-N_(a))/(2)(10-4)/(2)=3` (iv) Molecule has no unpaired electrons hence, it is DIAMAGNETIC. |
|