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Displacement (in metre) of a particle varies with time (in second) is given as y(t)= 4t ^(2) - 16t +5.Time taken by the particle to come to rest is……. |
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Answer» Solution :`y (t) = 4T ^(2) - 16 t + 5` `therefore v (t) = (d)/(DT) [ 4t ^(2) - 16 t +5]` `therefore v (t) = 8t - 16` If `v (t) =0 ` then time is .t. `therefore 0= 8t. -16` `therefore t.=2` second |
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