1.

Displacement (in metre) of a particle varies with time (in second) is given as y(t)= 4t ^(2) - 16t +5.Time taken by the particle to come to rest is…….

Answer»

4S
3 s
6 s
2 s

Solution :`y (t) = 4T ^(2) - 16 t + 5`
`therefore v (t) = (d)/(DT) [ 4t ^(2) - 16 t +5]`
`therefore v (t) = 8t - 16`
If `v (t) =0 ` then time is .t.
`therefore 0= 8t. -16`
`therefore t.=2` second


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