InterviewSolution
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InterviewSolution
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Displacement of a particle executing SHM s `x= 10 ( cos pi t + sin pi t)`. Its maximum speed isA. 10 cmB. 20 cmC. `5 sqrt(2)` cmD. 50 cm |
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Answer» Correct Answer - A Here, `x = 5 sqrt(2) (sin 2 pi t + cos 2 pi t)` `rArr" "x = 5 sqrt(2) sin 2 pi t + 5 sqrt(2) cos 2 pi t" "...(i)` The standard equation of simple harmonic motion is given by `x = A_(1) sin omega t + A_(2) cos omega t" "...(ii)` Now, comparing Eqs. (i) and (ii), we obtain `A_(1)=5 sqrt(2) and A_(2)=5 sqrt(2)` So, the resultant amplitude of the motion `A = sqrt(A_(1)^(2)+A_(2)^(2))=sqrt((5 sqrt(2))^(2)+(5 sqrt(2))^(2))= 10` cm |
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