1.

Displacement of particle changes with respect to time according to equation x =ae ^(-alpha t) + be ^(betat)where a, b, a and Bare positive constants, then velocity of particle is ......

Answer»

indipendent of `alpha and beta`
will be zero if `alpha = beta.`
will increase with repsect to time.
will increase with respect to time.

SOLUTION :`x = AE ^(-alphat ) + be ^(beta t )`
`therefore (DX)/(dt) =a (e ^(- alpha t )) (-alpha ) + B ( e ^(beta r )) (beta)`
`therefore v =- aalpha e ^(- alpha t ) + b beta e ^(beta t )`
`= b beta e ^(beta t )- a alpha e ^(- alpha t)`
`= b beta e ^(beta t) - (a alpha)/(e ^(alpha t))`
THUS, `(a alpha )/(e ^(alpha t))` will increase with increase of t and velocity will increase.


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