Displacement of SHM particle is x= 5 sin pi t where x is in cm. Then how much time taken by the particle from the mean position to at maximum displacement.

Displacement of SHM particle is x= 5 sin pi t where x is in cm. Then h

1.	Displacement of SHM particle is x= 5 sin pi t where x is in cm. Then how much time taken by the particle from the mean position to at maximum displacement.
Answer» SOLUTION :`x= 5SIN pi t` Maximum distance x= 5 cm `therefore 5= 5 SIN pi t` `therefore 1= sin pi t` `therefore (pi)/(2) = pi t` `therefore t= (1)/(2)s`.