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Displacement time equation of a particle executing `SHM` is, `x = 10 sin ((pi)/(3)t+(pi)/(6))cm`. The distance covered by particle in `3s` isA. `5cm`B. `20cm`C. `10cm`D. `15cm` |
Answer» Correct Answer - B `X = A sin (omegat +ph), T = (2pi)/(omega)` |
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