Displacement time equation of particle execution SHM is x=Asin(omegat +(pi)/6). Find the time taken by the particle to go directly from x=-A/2 to x=+A/2

Displacement time equation of particle execution SHM is x=Asin(omegat

1.	Displacement time equation of particle execution SHM is x=Asin(omegat +(pi)/6). Find the time taken by the particle to go directly from x=-A/2 to x=+A/2
Answer» Solution :PERIOD of oscillation is `T=(2pi)/(omega)` Now TIME TAKEN in GOING from mean position to `x=A/2` or from `x=A/2` to mean position comes out to be `T/12`. Therefore the DESIRED time will be `t=2(T/12)=T/6=(pi)/(3pomega)`