Displacement (y) of a body is represented byy = pt + qt^(2) - rt^(3)wherep,q and r are constants of motion. The velocity of the body when its acceleration is 0 :

Displacement (y) of a body is represented byy = pt + qt^(2) - rt^(3)wh

1.	Displacement (y) of a body is represented byy = pt + qt^(2) - rt^(3)wherep,q and r are constants of motion. The velocity of the body when its acceleration is 0 :
Answer» `p + (q^(2))/(2r)` `p + (q^(2))/(r)` `p + (q^(2))/(4R)` `p + (q^(2))/(3r)` Solution :Displacement y ` = PT + qt^(2) - rt^(3)` Velocity ` v = (dy)/(dt) = p + 2qt - 3rt^(2) "". . . (1)` Acceleration is ` a = (d^(2)y)/(dr^(2) )= 2Q - 6rt` When acceleration = 0 2q - 6rt = 0 `t = (2q)/(6r) = (q)/(3r)` Substituting the value of t in the EQUATION (1) we get , `v = p + 2q ((q)/(3r)) - 3r xx ((q)/(3r))^(2)` `:. v = p + (2q^(2))/(3r) - (3rq^(2))/(9r^(2))` Velocity`v = p + (2q^(2))/(3r) - (q^(2))/(3r)` `v = p + ((2q^(2) - q^(2))/(3r)) = p + (q^(2))/(3r)`