Dissipation factor for the dielectric is Df= ____(a) \(1.8×10^6\frac{σ}{f(MHz)}\)(b) \(1.8 \frac{σ}{f(MHz)}\)(c) \(1.8×10^6\frac{σ}{f(GHz)}\)(d) \(1.8×10^3\frac{σ}{f(MHz)}\)The question was posed to me by my college director while I was bunking the class.This intriguing question originated from Radio Wave Propagation topic in portion Radio Wave Propagation of Antennas

Dissipation factor for the dielectric is Df= ____(a) \(1.8×10^6\frac{

1.	Dissipation factor for the dielectric is Df= ____(a) \(1.8×10^6\frac{σ}{f(MHz)}\)(b) \(1.8 \frac{σ}{f(MHz)}\)(c) \(1.8×10^6\frac{σ}{f(GHz)}\)(d) \(1.8×10^3\frac{σ}{f(MHz)}\)The question was posed to me by my college director while I was bunking the class.This intriguing question originated from Radio Wave Propagation topic in portion Radio Wave Propagation of Antennas
Answer» Right choice is (a) \(1.8×10^6\FRAC{σ}{f(MHZ)}\) For explanation: DISSIPATION factor for the DIELECTRIC is Df = \(1.8×10^6\frac{σ}{f(MHz)}\), σ is the conductivity of earth. This is used to calculate the phase constant for the surface wave given by \(b=tan^{-1}(\frac{ϵ+1}{D_f})\)

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