1.

Dissociation constant of water at 25^(@)C is

Answer»

`1.0 xx 10 ^(-14) `
` 1xx 10 ^(14)`
` 14`
`1.8xx 10^(-16) `

SOLUTION :` K_(DISS)=(K_W)/( 55.5)=(1xx 10^(-14))/( ((1000)/(18)) )= 18 xx 10^(-17)= 1.8 xx 10 ^(-16)`


Discussion

No Comment Found