Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solution of density `1.15 g mL^(-1)`. The molarity of solution is:A. `1.78 M`B. `1.02 M`C. `0.50 M`D. `2.05 M`

Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solu

1.	Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solution of density `1.15 g mL^(-1)`. The molarity of solution is:A. `1.78 M`B. `1.02 M`C. `0.50 M`D. `2.05 M`
Answer» Correct Answer - D `n_("urea") = ("Mass"_("urea"))/("Molar mass"_("urea")) = (120g)/(60g mol^(-1)) = 2 "mol"` Volume of solution `= ("Mass of solution")/("Density of solution")` `= ((120+1000)g)/(1.15g mL^(-1)) = 974 mL = 0.974 L` Molarity `= ("Moles of urea")/("Liters of solution") = (2 mol)/(0.974L)` `= 2.05 "mol" L^(-1) = 2.05M`

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Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solution of density `1.15 g mL^(-1)`. The molarity of solution is:A. `1.78 M`B. `1.02 M`C. `0.50 M`D. `2.05 M`

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