Distance between the points on the curve 4x2+9y2=1, where tangent is p – InterviewSolution

1.	Distance between the points on the curve 4x2+9y2=1, where tangent is parallel to the line 8x=9y, is 2√k, unit, then k=
Answer» Distance between the points on the curve $4 x^{2} + 9 y^{2} = 1,$ where tangent is parallel to the line $8 x = 9 y,$ is $\frac{2}{\sqrt{k}},$ unit, then $k =$

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