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Distance between two bodies A and B is r. The gravitational force acting on them is inversely proportional to the square of distance. Gravitational force between them varies universally as the 4^(th) power of distance then find the accleration of body A. |
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Answer» SOLUTION :`IMPLIES`According to inverse law of square of DISTANCE, the gravitational force between A and B is `F = G(m_Am_B)/r^2""...(1)` `implies` ACCELERATION of body `a_A=F/m_A=(Gm_B)/r^2....(2)` For second case : `F. =G(m_Am_B)/r^4` Acceleration of A `a._A=(F.)/m_A =(Gm_B)/r^4=1/r^2((Gm_B)/r^2)` `:. a._A=(a_A)/r^2` |
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