1.

Distance between two bodies A and B is r. The gravitational force acting on them is inversely proportional to the square of distance. Gravitational force between them varies universally as the 4^(th) power of distance then find the accleration of body A.

Answer»

SOLUTION :`IMPLIES`According to inverse law of square of DISTANCE, the gravitational force between A and B is
`F = G(m_Am_B)/r^2""...(1)`
`implies` ACCELERATION of body `a_A=F/m_A=(Gm_B)/r^2....(2)`
For second case :
`F. =G(m_Am_B)/r^4`
Acceleration of A `a._A=(F.)/m_A =(Gm_B)/r^4=1/r^2((Gm_B)/r^2)`
`:. a._A=(a_A)/r^2`


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