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Distance of point `P(-2,3,4)` from the line `(x+2)/3=(2y+3)/4=(3z+4)/5` measured parallel to the plane `8x+6y-9z+1=0` isA. `(sqrt(301))/2`B. `(sqrt(401))/2`C. `(sqrt(307))/2`D. `(sqrt(207))/2` |
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Answer» Correct Answer - B `(x+2)/3=(y+3/2)/2=(z+4/3)/(5/3)=lamda`…………(1) `P(-2,3,4)` any variable point on line (1) `A(3lamda-2,2lamda-3/2, 5/3lamda-4/3)` no line `AP` and normal of given plane are perpendicular `implies (3lamda)8+((4lamda-9)/2)6+((5lamda-16)/3)(-9)=0` `implieslamda=-1` Distance `=sqrt(401)/2` |
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