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(Distributive laws) For any three sets A, B, C prove that: I. A∪(B∩C)=(A∪B)∩(A∪C) [Distirbutive law of union over intersection] II. A∩[(B∪C)]=(A∩B)∪(A∩C) [Distributive law of intersection over union] |
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Answer» (Distributive laws) For any three sets A, B, C prove that: I. A∪(B∩C)=(A∪B)∩(A∪C) II. A∩[(B∪C)]=(A∩B)∪(A∩C) |
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