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Divide 184 into two parts such that one-third of one part may exceed one-seventh of the other part by 8. |
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Answer» Let the two parts are `x` and `184-x`. then, `x/3 = 1/7(184-x)+8` `=>7x = 3((184-x)+56)` `=>7x = 552-3x+168` `=>10x = 720` `=> x = 72` So, other part = `184 - 72 = 112`. So, two parts are `72` and `112`. |
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