InterviewSolution
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InterviewSolution
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Divide `27x^(3) -81x^(2) + 45x + 23 " by " (x -2)` |
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Answer» `x = 2 {:(27 " -81 45 23"),(ul(0 " 54 -54 -18")),(27 " -27 -9 5 remainder"):}` coefficients of quotient step1: We first write the coefficients of the dividend arranging them in descending powers of x with zero as the coefficient for missing power of x step2 : To divide by `x -2`, we write `x = 2` Step 3: Bring down the leading coefficient of the dividend, multiply by 2 and add the second coefficient which result `- 27` Step 4: Now multiply `-27` by 2 and add this to the third coefficient to get `-9` Step 5 : This process is continued unit the final sum Step 6: Thus, we get the quotient as `27x^(2) - 27x - 9` and the remainder as 5 |
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