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Divide:6x3y3z2 by 3x2yz

Answer»

\(\frac{6x^3y^3z^2}{3x^2yz}\) = \((\frac{6}{3}x^{3-2}y^{3-1}z^{2-1})\) = 2xy2z [Using an ÷ am = an-m]



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