1.

Divide Rs. 2379 into 3 parts so that their amounts after 2, 3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is?

Answer»

Rs. 828



Let the parts be X, y and [2379 - (x + y)]

x + (x * 2 * 5/100) = y + (y * 3 * 5/100) = z + (z * 4 * 5/100)

11x/10 = 23y/20 = 6z/5 = k

x = 10k/11, y = 20k/23, z = 5k/6

But x + y + z = 2379

10k/11 + 20k/23 + 5k/6 = 2379

k = (2379 * 11 * 23 * 6)/3965 = (3 * 11 * 23 * 6)/5

x = [10/11 * (3 * 11 * 23 * 6)/5] = 828

Hence, the first part is Rs. 828.



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