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Divide the number 24 into two parts such that the ratio of their product to the sum of their squares is 3:10 |
Answer» according to question`(x*(24-x))/(x^2+(24-x)^2)=3/10` `10x(24-x)=3x^2+3(24-x)^2` `16x^2-384x+1728=0` `16(x^2-24x+108)=0` `x(x-18)-6(x-18)=0` `(x-6)(x-18)=0` `x=6,18` so the required numbers are 6 and 18. |
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