Do you expect different products in solution when aluminium (III) chloride and potassium chloride treated separately with (i) normal water (ii) acidified water and (iii) alkaline water ? Write equations wherever necessary.

Do you expect different products in solution when aluminium (III) chlo

1.	Do you expect different products in solution when aluminium (III) chloride and potassium chloride treated separately with (i) normal water (ii) acidified water and (iii) alkaline water ? Write equations wherever necessary.
Answer» SOLUTION :`AlCl_3` : The aqueous solution containing acidic nature. (i)`AlCl_(3(s)) + H_2O_((l)) to Al(OH)_(3(s)) + 3H_((aq))^(+) + 3Cl_((aq))^(-)` (ii) In acidified water `H^+` ion react with `Al(OH)_3` and give `Al^(3+)` in and `H_2O`. Thus the `Al^(3+)` and `Cl^-` ion obtain from `AlCl_3` in acidified water. (III)`AlCl_(3(s)) underset"water"OVERSET"Basic" to [Al(OH)_4]_((aq))^(-) + 3Cl_((aq))^(-)` `[Al(OH)_4]_((aq))^(-) to AlO_(2)^(-) + 2H_2O_((l))` KCl : KCl is a salt of strong acid and strong base and reacts with `H_2O`. The `K^+` and `Cl^-` obtain by only DISSOCIATION reaction. `KCl_((s)) overset(H_2O)to K_((aq))^(+) + Cl_((aq))^(-)` The aqueous solution of KCl is neutral. There is no reaction between ions in acidic/basic solution of KCl.