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doubt in 9 |
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Answer» y = log10(-1 + 1 + |x - 1/2|) To defined log x, we have -1 + |x - 1/2| > 0 ⇒ |x - 1/2| > 1 ⇒ x - 1/2 > 1 or x - 1/2 < - 1 ⇒ x > 3/2 or x < -1/2 ⇒ x \(\in\) (\(-\infty, \frac{-1}2\)) U (3/2, \(\infty\)) Domain of y is (-\(\infty\), -1/2) U (3/2, \(\infty\)) |
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