ΔPQR is right angled at Q. S is the mid-point of QR and PR2=a(PS)2+b(

1.	ΔPQR is right angled at Q. S is the mid-point of QR and PR2=a(PS)2+b(PQ)2 Then a + b is equal to:
Answer» $Δ P Q R$ is right angled at Q. S is the mid-point of QR and $P R^{2} = a (P S)^{2} + b (P Q)^{2}$ Then a + b is equal to:

ΔPQR is right angled at Q. S is the mid-point of QR and PR2=a(PS)2+b(PQ)2 Then a + b is equal to:

Answer»

$Δ P Q R$ is right angled at Q. S is the mid-point of QR and $P R^{2} = a (P S)^{2} + b (P Q)^{2}$

Then a + b is equal to: