Draw a graph of log P vs log (1/V) for a fixed amount of a gas at constant temperature.

Draw a graph of log P vs log (1/V) for a fixed amount of a gas at cons

1.	Draw a graph of log P vs log (1/V) for a fixed amount of a gas at constant temperature.
Answer» Solution :According to BOYLE's LAW `P=(k)/(V)` take log of both sides we have log `P=log((1)/(V))+logk` ltbr. Comparing it to `y=mx+C` w FIND that GRAPH between log P vs. log (1/V) should be a STRAIGHT line with slop equal to log.