Saved Bookmarks
| 1. |
Draw formulas for the first five members of each homologous series beginning with the following compounds. (a) HCOOH (b) CH_(3)COCH_(3) (c ) H- CH = CH_(2) |
|
Answer» Solution :(a) (i) HCOOH (ii) `CH_(3)COOH` (iii) `CH_(3)-CH_(2)-COOH` (iv) `CH_(3)-CH_(2)-CH_(2)-COOH` (V) `CH_(3)-CH_(2)-CH_(2)-CH_(2)-COOH` (b) (i) `CH_(3)COCH_(3)` (ii) `CH_(3)COCH_(2)CH_(3)` (iii) `CH_(3)COCH_(2)CH_(2)CH_(3)` (iv) `CH_(3)COCH_(2)CH_(2)CH_(2)CH_(3)` (v) `CH_(3)COCH_(2)CH_(2)CH_(2)CH_(2)CH_(3)` (c ) (i) `H-CH= CH_(2)` (ii) `CH_(3)-CH= CH_(2)` (iii) `CH_(3)-CH_(2)-CH= CH_(2)` (iv) `CH_(3)-CH_(2)-CH_(2)-CH= CH_(2)` (v) `CH_(3)- CH_(2) - CH_(2) - CH_(2) - CH= CH_(2)` |
|