Draw MO diagram of CO and calculate its bond order .

1.	Draw MO diagram of CO and calculate its bond order .
Answer» Solution :(i) ELECTRONIC configuration of C ATOM: `1s^(2) 2s^(2)2P^(2)` Electronic configuration of O atom: `1s^(2)2s^(2)2p^(4)` (ii) Electronic configuration of CO molecule is: `sigma 1s^(2)" " sigma 1s^(2)" "sigma2s^(2)" "sigma2s^(2)" "pi 2p_(y)^(2)" "pi2p_(z)^(2)" "sigma2p_(x)^(2)` (iii) Bond order `= (N_(b)- N_(a))/(2)(10-4)/(2)=3` (iv) Molecule has no unpaired ELECTRON, hence it is DIAMAGNETIC.

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