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Draw the complete structures of bromomethane, bromoethane, 2 -bromopropane and tertbutyl bromide. Arrange them in order of increasing steric hindrance. |
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Answer» Solution :(i) Bromomethane, `CH_3 Br: H- UNDERSET(underset(H)|)overset(overset(H)|)C - Br` (ii) Bromoethane, `CH_3 CH_2 Br:H - underset(underset(H)|)overset(overset(H)|)C - underset(underset(H)|)overset(overset(H)|)C - Br` (iii) 2- Bromopropane, `CH_3 CH Br CH_3 : H - underset(underset(H)|)overset(overset(H)|)C- underset(underset(Br)|)overset(overset(H)|)C - underset(underset(H)|)overset(overset(H)|)C- H` (IV) tert-Butyl bromide, `(CH_3)_3 Br: H- underset(underset(H)|)overset(overset(H)|)C - underset(underset(H-underset(underset(H)|)C-H)|)overset(overset(H-overset(overset(H)|)C-H)|)C - Br` Increasing order of STERIC hindrance : Bromomethane < Bromoethane < 2-Bromopropane < tert-Butyl bromide. |
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