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| 1. |
Draw the free body diagram that represents the particle accelerating in positive xdirection |
Answer» Solution :The RELATIVE magnitude of forces should be INDICATED when the free body diagram for mass m is drawn.  Case (a): The forces `F_1`and `F_2`have equal LENGTH but opposite direction. So net force along y-direction is ZERO. Since the force is zero, acceleration is also zero along Y-direction (Newton.s second law). Similarly in the x direction, `F_3` and `F_4`have equal length and opposite in direction. So net force is zero in the x direction. So there is no acceleration in x direction. Case (b): The forces `F_1` and `F_2`are not equal in length and act opposite to each other. The figure (b) shows that there are unbalanced forces along the y-direction. So the particle has acceleration in the y-direction. The forces `F_3` and `F_4`are having equal length and act in opposite directions. So there is no net force along the x direction. So the particle has no acceleration in the x direction. Case (c): The forces `F_1` and `F_2`are equal in magnitude and act opposite to each other. The net force is zero in y direction. So in y-direction there is no acceleration. The forces `F_3` and `F_4`are not equal in magnitude and `F_3` is greater than `F_4` . So there is a net acceleration in NEGATIVE x direction Case (d): The forces `F_1`and `F_2`are equal in magnitude and act opposite to each other. The net force is zero in y direction. So there is no acceleration in y-direction. The forces `F_3` and `F_4`are not equal in magnitude. The force `F_4`is greater than the force `F_3`. So there is a net acceleration in the positive x direction. |
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