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Draw the graph of f(x)=[cot^(-1)x]," where "[*] representsthe greatest integer funtion. |
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Answer» Solution :Given `F(X)=[cos^(-1)x]` `cot^(-1)x`is a decreasing function in R. So `[cot^(-1)x]` is discontinuous whn `cot^(-1)x` is an interger. Now `0lecot^(-1)x lepi" for "x in R` So `[cot^(-1)x]` is discontinuous when`cot^(-1)x=1,2,3` or`x=cot1, cot2, cot3` When `[cot^(-1)x]=0,0lecot^(-1)xlt1:.cot1ltxleoo` When `[cot^(-1)x]=1,1lecot^(-1)xlt2:.cot2ltxlecot1` ltbrtgt When `[cot^(-1)x]=2,2lecot^(-1)xlt3:.cot3ltxlecot2` `[cot^(-1)x]=3,3lecot^(-1)xltpi:.-ooltxlecot3` So the graph of `f(x)[cot^(-1)x]` can be DRAWN as FOLLOWS.
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