InterviewSolution
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InterviewSolution
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Draw the graph of y = e^(x) sin 2pix. |
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Answer» Solution :We have `y = f(x) = e^(x) sin 2PIX` First draw the GRAPH of `y = +-e^(x).` Now `sin 2pix = 0` when `2pix = npi` or x = n/2, where `n in Z` Also `sin 2pix = 1` for `2 pix = (4n + 1) (PI)/(2)` or `x = n + (1)/(4), n in Z` and `sin 2pix = - 1` for `2 pix = (4n - 1) (pi)/(2)` or `x = n - (1)/(4), n in Z` For `f(n + (1)/(4)) = e^(n + (1)/(4))` and `f(n - (1)/(4)) = -e^(n + (1)/(4))` All points `f(n + (1)/(4), e^(n + (1)/(4)))` lie on the graph of `y = e^(x)` and all points `f(n - (1)/(4), -e^(n - (1)/(4)))` lie on the graph of `y = -e^(x)` Thus, the graph of the function is as shown in the following figure. 
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