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Draw the Lewis dot structure of HCNmolecule. |
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Answer» Solution :Solution . STEP .1. Total NUMBER of valence electons in HCN = 1 + 4 + 5 = 10 `(""_(1)H= 1, ""_(6)C= 2 , 4,""_(7)N =2 ,5)` Step 2. Skeletal structure is HCN(C is least electronegative). Step 3. Putting ONE shared pair of electons between H and C and between C and N, and the remaining as LONE pairs, we have ![]() In the structure, duplet of H is complete but octets of CAND N are not complete .Hence, multiple bonding is required between C and N. Octets of C and N will be complete if three is triple bond between C and N. Thus. .
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