Draw the M.O diagram for oxygen molecule and calculate its bond order and show that O_(2) is paramagnetic.

Draw the M.O diagram for oxygen molecule and calculate its bond order

1.	Draw the M.O diagram for oxygen molecule and calculate its bond order and show that O_(2) is paramagnetic.
Answer» SOLUTION :(i) Electronic configuration of O atom is `1S^(2) 2s^(2) 2p^(4)` (ii) Electronic configuration of `O_(2)` molecule is `sigma 1s^(2) sigma^() 1s^(2) sigma^()2s^(2) sigma2p_(x)^(2) pi 2p_(y)^(2) pi2p_(z)^(2) pi^()2p_(y)^(1) pi^() 2p_(z)^(1)` (iii) Bond order `= (N_(b) - N_(a))/(2) = (10-6)/(2) =2` (iv) Molecule has two unpaired ELECTRONS, hence it is paramagnetic.