Draw the M.O diagram for oxygen molecule calculate its bond order and show that O_(2) is paramagnetic.

Draw the M.O diagram for oxygen molecule calculate its bond order and

1.	Draw the M.O diagram for oxygen molecule calculate its bond order and show that O_(2) is paramagnetic.
Answer» Solution :(i) ELECTRONIC configuration of O atom is `1s^(2)2s^(2)2p^(4)` (ii) Electronic configuration of `O_(2)` molecule is `sigma 1s^(2)" "sigma1s^(2)" "sigma2s^(2)" "sigma2s^(2)" "sigma2p_(x)^(2)" "pi2p_(Z)^(2)" "pi2p_(y)^(1)" " pi2p_(z)^(1)` (iii) Bond order `=(N_(B)-N_(a))/(2)=(10 - 6 )/(2)=2` (iv) Mole cule has two unpaired electrons, hence it is paramagnetic.