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Draw the MO diagram for acetylide ion C_(2)^(2-) and calculate its bond order. |
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Answer» Solution :Acetylide ion, `C_(2)^(2-)` in ACETYLENE: `UNDERSET(1s^(2)" "2s^(2)" "2p^(4))(C)rarrunderset(1s^(2)" "2s^(2)" "2p^(2))(C^(2-)+2e)` Electronic configuration of `C_(2)^(2-)` ion is : `SIGMA 1s^(2) sigma **1s^(2)sigma1s^(2) pi2p_(x)^(2)pi2p_(y)^(2)` Bond order `= (N_(B)-N_(a))/(2)=(8-4)/(2)=2` |
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