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Draw the structure of BrF3 on the basis of VSEPR Theory |
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Answer» on the basis of vsepr theory,no. of electron pairs=(V+M-C)÷2Where V is the no. of valence electrons in central atomM is the no. of monovalent atomsC is the numerical charge on the whole molecule so, in this case,no. of valence electrons in central atom(Br)=7the no. of monovalent atoms(F)=3charge=0 thus, no. of electron pairs=(7+3-0)÷2=5in the atom Br is bonded to 3 atoms of fluorine. hence no. of bond pairs=3no. of lone pairs=2 This implies that BrF3 will have a trigonal bipyramidal geometry and a T-shape.T refers to the english alphabet "T" HOPE THIS HELPS!! :-) |
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