Drew the M.O diagram of oxygen molecule. Calculate its bond order and magnetic character. (ii) Draw and explain the graph obtained by plotting solubility versus temperature for calcium chloride.

Drew the M.O diagram of oxygen molecule. Calculate its bond order and

1.	Drew the M.O diagram of oxygen molecule. Calculate its bond order and magnetic character. (ii) Draw and explain the graph obtained by plotting solubility versus temperature for calcium chloride.
Answer» SOLUTION : (i) 1. Electronic CONFIGURATION of O atom is `1s^2 2s^2 2p^4` 2. Electronic configuration of `O_2` molecule is `sigma 1s^2 sigma^1s^2 sigma2s^2 sigma^2s^2 sigma2p_x^2 pi2p_y^2 pi2p_z^2 pi^2p_y^1 pi^2p_x^1` 3. Bond ORDER `=(N_b-N_a)/(2) = (10-6)/(2)=2` 4. Molecular has two unpaired electrons , hence it is paramagnetic (ii) Even though the dissolution of calcium CHLORIDE is exothermic , the solubility increases moderately with increase in temperature.Here, the entropy FACTOR also plays a significant role in deciding the position of the equilibrium