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Drope of water fall at regular intervals from the roof of a building of height H=16m, the first dro striking the ground at the same moment as the fifth drop detaches from the roof. Find the distance between the successive drops. |
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Answer» Solution :Step-I : Time TAKEN by the first • 5 drop to touch the ground = `t=sqrt((2h)/(g))` • 4 For `h=16m,t=sqrt((2xx16)/(g))=4sqrt((2)/(g))` • 3 Time interval between two drops is • 2 `t_("interval")=((1)/(n-1))t=((1)/(4))t=sqrt((2)/(g))` • 1 Where n =number of drops Step - II : Distance between first and second drops `=S_(1)-S_(2)=(1)/(2)g t_("interval")^(2)[4^(2)-3^(2)]=7m` Distance between second and third drops `=S_(2)-S_(3)=(1)/(2)g t_("interval")^(2)[3^(2)-2^(2)]=5m` Distance between third and fourth drops `=S_(3)-S_(4)=(1)/(2)g t_("interval")^(2)[2^(2)-1^(2)]=3m` Distance between fourth and FIFTH drops. `=S_(4)-S_(5)=(1)/(2)g t_("interval")^(2)[1^(2)-0]=1m`. |
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