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Drope of water fall at regular intervals from the roof of a building of height H=16m, the first dro striking the ground at the same moment as the fifth drop detaches from the roof. Find the distance between the successive drops.

Answer» <html><body><p></p>Solution :Step-I : Time <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> by the first • <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> <br/> drop to touch the ground = `t=sqrt((2h)/(g))` • 4 <br/> For `h=16m,t=sqrt((2xx16)/(g))=4sqrt((2)/(g))` • <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> <br/> Time interval between two drops is • 2 <br/> `t_("interval")=((1)/(n-1))t=((1)/(4))t=sqrt((2)/(g))` • 1 <br/> Where n =number of drops <br/> Step - <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a> : <br/> Distance between first and second drops <br/> `=S_(1)-S_(2)=(1)/(2)g t_("interval")^(2)[4^(2)-3^(2)]=7m` <br/> Distance between second and third drops <br/> `=S_(2)-S_(3)=(1)/(2)g t_("interval")^(2)[3^(2)-2^(2)]=5m` <br/> Distance between third and fourth drops <br/> `=S_(3)-S_(4)=(1)/(2)g t_("interval")^(2)[2^(2)-1^(2)]=3m` <br/> Distance between fourth and <a href="https://interviewquestions.tuteehub.com/tag/fifth-987488" style="font-weight:bold;" target="_blank" title="Click to know more about FIFTH">FIFTH</a> drops. <br/> `=S_(4)-S_(5)=(1)/(2)g t_("interval")^(2)[1^(2)-0]=1m`.</body></html>


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