1.

Drops of water fall at regular intervals from the roof of a building of height H = 16m, the first drop striking the ground at the same moment as the fifth drop detaches from the roaf. Find the distance between the successive drops.

Answer»

Solution :Step -I : Time taken by the first
drop to touch the ground `=t=sqrt((2h)/g) `
For h=16m, `t=sqrt((2 XX 16)/g) =4sqrt(2/g)`
Time interval between two drops is
`t_("interval")=((1)/(n-1))t=(1/4)t=sqrt(2/g)`
where n=number of drops.
Step -ii : DISTANCE between first and SECOND drops
`=S_(1)-S_(2)=1/2 gt_("interval")^(2) [4^(2)-3^(2)]=7M`
Distance between second and third drops
`=S_(2)-S_(3)=1/2 "gt"_("internal")^(2) [3^(2)-2^(2)]=5m`
Distance between third and fourth drops
`=S_(3)-S_(4)=1/2 "gt"_("internal")^(2) [2^(2)-1^(2)]=3m`
Distance between fourth and fifth drops
`=S_(4)-S_(5)=1/2 "gt"_("interval")^(2) [1^(2)-0]=1m`.


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