InterviewSolution
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Dry air was passed successively through solution of `5g` of a solute in `180g` of water and then through pure water. The loss in weight of solution was `2.50 g` and that of pure solvent `0.04g`. The molecualr weight of the solute is:A. (a) `31.25`B. (b) `3.125`C. (c ) `312.5`D. (d) None of these |
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Answer» Correct Answer - A `P^(@)-P_(S) prop` loss in weight of water chamber and `P_(S) prop` loss in `wt`. of solution chamber. `(P^(@)-P_(S))/(P^(@)) = (n)/(N) = (w xx M)/(m xx W)` or `(0.04)/(2.50) = (5 xx 18)/(m xx 180)` `:. m = 31.25` |
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