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Due to a small magnet intensity at a distance `x` in the end on position is `9` Gauss. What will be the intensity at a distance `(x)/(2)` on broad side on position?A. 9 gaussB. 4 gaussC. 36 gaussD. 4.5 gauss |
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Answer» Correct Answer - C In CGS`,B_("axial")=9=(2M)/(x^(3))` ...........(i) ` B_("equatorial")=(M)/(((x)/(2))^(2))=(8M)/(x^(3))` ........(ii) From Eq. (i) and (ii) , `B_("equatorial")=36`gauss |
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