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Due to a small magnet intensity at a distance `x` in the end on position is `9` Gauss. What will be the intensity at a distance `(x)/(2)` on broad side on position?A. 9 gaussB. 4 gaussC. 36 gaussD. 4.5 gauss

Answer» Correct Answer - C
In CGS`,B_("axial")=9=(2M)/(x^(3))` ...........(i)
` B_("equatorial")=(M)/(((x)/(2))^(2))=(8M)/(x^(3))` ........(ii)
From Eq. (i) and (ii) , `B_("equatorial")=36`gauss


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