During a projectile motion if the maximum height equals the horizontal range,then the angle of projection with the horizontal is :

During a projectile motion if the maximum height equals the horizontal

1.	During a projectile motion if the maximum height equals the horizontal range,then the angle of projection with the horizontal is :
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a>^(-1) (1)` <br/>`tan^(-1) (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/>`tan^(-1) (3)` <br/>`tan^(-1) (4)` </p>Solution :`(u^(2) <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> ^(2) theta)/(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>)= (u^(2) sin 2 theta)/(g)`<br/>`:. (sin^(2)theta)/(2) = 2 sin theta <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta`<br/>`:. (sin theta)/( cos theta) = 4`<br/>`tan theta = 4`<br/>`:. theta = tan^(-1)(4)`</body></html>