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During an adiabatic process, if the pressure of an ideal gas is proportional to the cube of its temperature, find gamma . |
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Answer» <P> Solution :For an ideal gas of one MOLE `PV=RT^(3)`During an ADIABATIC process `P oo T^(3) rArr P=KT^(3)` `P=K((PV)/(R ))^(3)rArr P=((K)/(R^(3)))P^(3)V^(3)` `P^(2)V^(3)=` constant`""PV^(3//2)=` constant Comparing it with the equation `PV^(gamma) =` constant for an adiabatic process, we get `gamma=3//2` |
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