1.

During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of (C_(P))/(C_(V)) for the gas is

Answer»

`(5)/(3)`
`(3)/(2)`
`(4)/(3)`
2

Solution :`P prop T^(3)`
`PT^(-3)` = constant …(i)
For an adiabatic process, `PT^(gamma//1-gamma)` = constant …(ii)
Comparing (i) and (ii), we get
`(gamma)/(1-gamma) = -3` or `gamma = -3 + 3gamma` or `-2gamma = -3` or `gamma = (3)/(2)`
As `gamma = (C_(P))/(C_(V)) :. (C_(P))/(C_(V)) = (3)/(2)`


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