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During an adiabatic process, the the pressure of a mixture of monatomic and diatomic gases is found to be proportional to the cube of the temperature . Find the value of gamma=(C_P//C_V) |
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Answer» Solution :In adiabatic PROCESS , `T^(gamma)P^(1-gamma)="conatant"` `PT^(-3)="CONSTANT" ` .....(1) `gamma/(PT^(1-gamma))="constant"` ....(2) `gamma/(PT^(1-gamma))=PT^(-3)` Comparing the powres, `gamma/(1-gamma)=-3=-3+3gamma` `2gamma=3,gamma=3/2` |
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