During complete combustion of one mole of butane, 2658kJ of heatis released. The thermochemical reaction for above changeis

During complete combustion of one mole of butane, 2658kJ of heatis rel

1.	During complete combustion of one mole of butane, 2658kJ of heatis released. The thermochemical reaction for above changeis
Answer» `2C_(4)H_(10)(G)+13O_(2)(g) rarr 8 CO_(2)(g) +10 H_(2)O(l) Delta_(c) H=- 2658.0 kJ mol^(-1)` `C_(4)H_(10)(g)+ (13)/(2) O_(2)(g) rarr4CO_(2)(g)+5H_(2)O(g) Delta_(c)H=- 1329.0 kJ mol^(-1)` `C_(4)H_(10)(g)+ (13)/(2) O_(2)(g) rarr4CO_(2)(g)+5H_(2)O(l) Delta_(c)H=- 2658.0 kJ mol^(-1)` `C_(4)H_(10)(g)+ (13)/(2) O_(2)(g) rarr4CO_(2)(g)+5H_(2)O(l) Delta_(c)H=+ 2658.0 kJ mol^(-1)` Solution :We have to take the combustion of one mole of `C_(4)H_(10)` and `Delta_(c) H`should be `-ve` and have a value of 2658 kJ mol`^(-1)`