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During estimation of nitrogen present in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5 g of the compound neutralized 10 mL of 1 M H_(2)SO_(4). Find the percentage of nitrogen in the compound. |
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Answer» SOLUTION :Volume of `H_(2)SO_(4)` used = 10 mL of `1 M H_(2)SO_(4)` Now`H_(2)SO_(4) + 2NH_(3) rarr (NH_(4))_(2)SO_(4)` Now 1 mole of `H_(2)SO_(4)` reacts with 2 moles of `NH_(3)`. `:.` 1- mL of `1M H_(2)SO_(4) -= 20 mL` of `1 M NH_(3)` Now 1000 mL of `1 M NH_(3)` contains `N = 14 g :. 20 mL` of `1 M NH_(3)` will contain `N =(14)/(1000) xx 20` But this amount of nitrogen is present in 0.5 g of the organic compound. `:.` Percentage of nitrogen `= (14 xx 20)/(1000) xx (100)/(0.5) = 56.0`. Alternatively, % age of `N = (1.4 xx "Vol. of acid used" xx "BASICITY of acid" xx "Molarity of acid")/("Mass of the SUBSTANCE taken") = (1.4 xx 10 xx 2 xx 1)/(0.5) = 56.0` |
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